If a base class pointer contains the address of a derived class object, then the pointer is called as Upcasted pointer & this process is called as Upcasting.

Let us look at a program to understand the concept of upcasting.

C++ Program For Upcasting

#include<iostream>
using namespace std;
class base{ 
 public: void display1(){ 
   cout<<"base - display1 n";
} void display2(){ 
   cout<<"base - display2 n";
} }; class der : public base{ 
 public: void display1(){ 
   cout<<"der - display1 n";
} void display2(){ 
   cout<<"der - display2 n";
} }; int main(){ 
base b, *bptr; 
bptr = &b;
bptr->display1(); bptr->display2();
der d; bptr = &d; //upcasting 
bptr->display1();
bptr->display2();
return 0; }

Output:-base – display1
base – display2
base – display1
base – display2

Explanation of the program

We have assigned the address of a derived class object to the base class pointer. Is this not an error, since we are assigning of one type to a pointer of another?

No, the rule is that derived object can be treated as a base object as well since derived object contains the base part.

So, in this case, the compiler relaxes the type checking. Note that we have used the following statement.

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